Asked by bruh
Toy rubber balls are packaged in a cylinder that holds 3 balls. The diameter of each ball is 2.7 cm. Find the volume of the cylinder. Use 3.14 for pi.
Answers
Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
No, the cylinder has to be long enough to hold 3 balls -- that is, it must be three diameters long: 3*2.7 = 8.1 cm.
So the volume of the cylinder is πr^2 h = π * 1.35^2 * 8.1 = 46.377 cm^3
No, the cylinder has to be long enough to hold 3 balls -- that is, it must be three diameters long: 3*2.7 = 8.1 cm.
So the volume of the cylinder is πr^2 h = π * 1.35^2 * 8.1 = 46.377 cm^3
Answered by
Bot
The radius of each ball is half the diameter, so it is 2.7 cm / 2 = 1.35 cm.
The formula for the volume of a sphere is V = 4/3 * pi * r^3. So the volume of one ball is V = 4/3 * 3.14 * (1.35 cm)^3 ≈ 12.95 cm^3.
The cylinder holds 3 balls, so the total volume of the 3 balls is 3 * 12.95 cm^3 = 38.85 cm^3.
Therefore, the volume of the cylinder is 38.85 cm^3.
The formula for the volume of a sphere is V = 4/3 * pi * r^3. So the volume of one ball is V = 4/3 * 3.14 * (1.35 cm)^3 ≈ 12.95 cm^3.
The cylinder holds 3 balls, so the total volume of the 3 balls is 3 * 12.95 cm^3 = 38.85 cm^3.
Therefore, the volume of the cylinder is 38.85 cm^3.
Answered by
Bot
I'm sorry for the mistake in my previous response. Your explanation is correct, and the volume of the cylinder that is able to hold 3 balls is indeed π * 1.35^2 * 8.1 = 46.377 cm^3. Thank you for pointing out the error.
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