Asked by Dara
If the area of a room is 169 cm square calculate its perimeter
Answers
Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
lots of unnecessary work, but you blew it at the end: 338/13 = 26, not 36.31
What a load of rubbish! No one asked for minimum perimeter. But even if they had, we all know that the perimeter is a minimum when the rectangle is a square. In this case, that means the side length is √169 = 13 cm
So the perimeter is 4*13 = 52cm
lots of unnecessary work, but you blew it at the end: 338/13 = 26, not 36.31
What a load of rubbish! No one asked for minimum perimeter. But even if they had, we all know that the perimeter is a minimum when the rectangle is a square. In this case, that means the side length is √169 = 13 cm
So the perimeter is 4*13 = 52cm
Answered by
Bot
Let's assume that the length of the room is L cm and the width of the room is W cm.
We know that the area of the room is:
A = L x W = 169 cm²
We want to find the perimeter of the room, which is the sum of all four sides:
P = 2L + 2W
To find L and W, we can use the fact that their product is 169:
LW = 169
We can solve for one of the variables, say L, in terms of the other:
L = 169/W
Substituting this into the equation for the perimeter:
P = 2(169/W) + 2W
Simplifying:
P = (338/W) + 2W
Now we can use calculus to find the value of W that minimizes the perimeter:
dP/dW = -338/W² + 2
Setting this equal to zero and solving for W, we get:
338/W² = 2
W² = 169
W = 13
Substituting this back into the equation for the perimeter:
P = (338/13) + 26
P ≈ 62.31 cm
We know that the area of the room is:
A = L x W = 169 cm²
We want to find the perimeter of the room, which is the sum of all four sides:
P = 2L + 2W
To find L and W, we can use the fact that their product is 169:
LW = 169
We can solve for one of the variables, say L, in terms of the other:
L = 169/W
Substituting this into the equation for the perimeter:
P = 2(169/W) + 2W
Simplifying:
P = (338/W) + 2W
Now we can use calculus to find the value of W that minimizes the perimeter:
dP/dW = -338/W² + 2
Setting this equal to zero and solving for W, we get:
338/W² = 2
W² = 169
W = 13
Substituting this back into the equation for the perimeter:
P = (338/13) + 26
P ≈ 62.31 cm
Answered by
Bot
I apologize for my mistake. You are correct. The perimeter of the room would be 52 cm. Thank you for pointing out the error.
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