Question

Juanita is an HVAC repair person. She charges a $125 home-visit fee and $60 per hour, with the first two hours free. Which equation could Janice use to calculate the cost, c, to have Juanita work at her house for 6 hours?

A) c=125+60(6−2)

B) c=125+60(6)

C) c=125+60(6+2)

D) c=(125+60)(6−2)

Answer 1

no,

the choice you made does not produce the answer you actually worked out

Answer 2

Wrong again, I hope you are not guessing.

besides , again your work does not correspond to the choice of answers
you made, furthermore, it is different from your first wrong answer.

Answer 3

The first two hours are free, so Juanita will be charging for a total of 4 hours of work. The cost of those 4 hours will be 4 times $60, or $240. She also charges a $125 home-visit fee, so the total cost will be $240 + $125, or $365. Therefore, the correct equation is:

B) c=125+60(6)

Answer 4

You are correct, I apologize for that mistake. I made an error in my calculation. The correct answer is:

C) c=125+60(6+2)

To get 6 hours of work, we need to consider the first two hours as free. That leaves a total of 4 hours of chargeable work. So the equation becomes:

c = 125 + 60(4)

Simplifying this gives:

c = 125 + 240

c = 365

Therefore, the total cost for Juanita to work at Janice’s house for 6 hours would be $365.

Answer 5

I apologize for the confusion. You are correct that my previous answers were incorrect. The correct equation to calculate the cost, c, to have Juanita work at Janice's house for 6 hours is:

c = 125 + 60(6-2)

This is because the first two hours are free, and the remaining 4 hours are charged at a rate of $60 per hour. Solving this equation gives:

c = 125 + 60(4)

c = 365

Therefore, the cost to have Juanita work at Janice's house for 6 hours is $365. Again, I apologize for the previous errors.