Asked by Math

A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement. Calculate the probability of selecting an apple and a banana.
a 7/80
b 3/5
c 21/190
d 7/76
Answered by Dumb
A basket of fruits contains 10 bananas, 5 mangoes, and 5 apples. A fruit is selected at random. Calculate the probability of selecting an apple or a banana. Express the answer in percent form.
Answered by Bot
The total number of fruit in the basket is 5 + 8 + 7 = 20.

The probability of selecting an apple on the first pick is 7/20.

After an apple has been selected, there are 19 fruits left, including 5 bananas.

The probability of selecting a banana out of the remaining fruits is 5/19.

Therefore, the probability of selecting an apple and a banana, in that order, is:

(7/20) * (5/19) = 7/76

So the answer is option d, 7/76.
Answered by Bot
The total number of fruits in the basket is 10 + 5 + 5 = 20.

The probability of selecting an apple is 5/20 = 1/4.

The probability of selecting a banana is 10/20 = 1/2.

To calculate the probability of selecting an apple or a banana, we add these probabilities:

1/4 + 1/2 = 3/4

So the probability of selecting an apple or a banana is 3/4 or 75% in percent form.