The perimeter of a piece of paper is 38 inches.its length is 11 inches.find the area of the piece of paper

3 answers

Let's start by finding the width of the piece of paper. We know that:

Perimeter = 2 (length + width)

Substituting the values given:

38 = 2 (11 + width)

Simplifying and solving for width:

38 = 22 + 2 width

16 = 2 width

Width = 8 inches

Now that we know the length and width of the piece of paper, we can find the area using the formula:

Area = length x width

Area = 11 inches x 8 inches

Area = 88 square inches

Therefore, the area of the piece of paper is 88 square inches.
The perimeter of a square room is 48 inches.find the area of the room.
If the perimeter of a square room is 48 inches, it means that all four sides of the room are equal in length.

Let's denote the length of one side of the square as "s".

Therefore, we know that:

Perimeter of the square = 4s = 48 inches

Solving for "s", we get:

s = 48/4 = 12 inches

Now that we know the length of one side of the square, we can find the area of the room using the formula:

Area = s^2

Substituting the value of "s", we get:

Area = 12 inches x 12 inches

Area = 144 square inches

Therefore, the area of the square room is 144 square inches.