(2^-1 . 7^-4)^-2
= (2^2)(7^8)
= 23059204
I need to simplify this.
(2^-1 . 7^-4)^-2
I thought that 2 was suppose to be multiplied with the -1, but that doesn't seem to make sense so I am confused. I know that PEDMAS needs to be used, just don't know how to apply it. Any help is appreciated!
5 answers
Those aren't any of my choices Here is what i got
2^2 . 7^8
2^5 . 7^5
1/2^5 . 7^5
1/2^2 . 7 ^8
2^2 . 7^8
2^5 . 7^5
1/2^5 . 7^5
1/2^2 . 7 ^8
sorry I went to the effort of calculating
2^2 . 7^8 for you.
2^2 . 7^8 for you.
Thanks! That is what I thought, but why is this the answer? How does the probelm work it self out to be like that?
multiply each of the inside terms by the outside term.
2^-1*1^-2 = combine exponents = 2^2
7^-4*1^-2 = combine exponents = 7^8
2^-1*1^-2 = combine exponents = 2^2
7^-4*1^-2 = combine exponents = 7^8
1 answer