Asked by Alicia
I need to simplify this.
(2^-1 . 7^-4)^-2
I thought that 2 was suppose to be multiplied with the -1, but that doesn't seem to make sense so I am confused. I know that PEDMAS needs to be used, just don't know how to apply it. Any help is appreciated!
(2^-1 . 7^-4)^-2
I thought that 2 was suppose to be multiplied with the -1, but that doesn't seem to make sense so I am confused. I know that PEDMAS needs to be used, just don't know how to apply it. Any help is appreciated!
Answers
Answered by
Reiny
(2^-1 . 7^-4)^-2
= (2^2)(7^8)
= 23059204
= (2^2)(7^8)
= 23059204
Answered by
Laurie
Those aren't any of my choices Here is what i got
2^2 . 7^8
2^5 . 7^5
1/2^5 . 7^5
1/2^2 . 7 ^8
2^2 . 7^8
2^5 . 7^5
1/2^5 . 7^5
1/2^2 . 7 ^8
Answered by
Reiny
sorry I went to the effort of calculating
2^2 . 7^8 for you.
2^2 . 7^8 for you.
Answered by
Laurie
Thanks! That is what I thought, but why is this the answer? How does the probelm work it self out to be like that?
Answered by
Anonymous
multiply each of the inside terms by the outside term.
2^-1*1^-2 = combine exponents = 2^2
7^-4*1^-2 = combine exponents = 7^8
2^-1*1^-2 = combine exponents = 2^2
7^-4*1^-2 = combine exponents = 7^8
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