Question
The highest pressure ever produced in a laboratory setting was about 2.0 x 106 atm. If we have a 1.0 x 10-5 liter sample of a gas at that pressure, then release the pressure until it is equal to 0.275 atm, what would the new volume of that gas be
Answers
We can use the Boyle's Law equation to solve for the new volume:
P1V1 = P2V2
Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Plugging in the given values, we get:
(2.0 x 10^6 atm)(1.0 x 10^-5 L) = (0.275 atm)(V2)
Solving for V2, we get:
V2 = (2.0 x 10^6 atm)(1.0 x 10^-5 L) / (0.275 atm)
V2 = 72,727.3 L
Therefore, the new volume of the gas at 0.275 atm pressure would be approximately 72,727.3 L.
P1V1 = P2V2
Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Plugging in the given values, we get:
(2.0 x 10^6 atm)(1.0 x 10^-5 L) = (0.275 atm)(V2)
Solving for V2, we get:
V2 = (2.0 x 10^6 atm)(1.0 x 10^-5 L) / (0.275 atm)
V2 = 72,727.3 L
Therefore, the new volume of the gas at 0.275 atm pressure would be approximately 72,727.3 L.
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