Question

A video streaming service announced that 40% of its subscribers in the United States watched its latest
documentary. Robert believes this proportion is higher for the subscribers living in Virginia. He randomly
selects a sample of subscribers to survey and finds that 148 out of 300 subscribers watched the
documentary. Assume all the conditions for performing a significance test with a z-statistic are met and
use a significance level of a=0.05 Calculate the p-value and make a conclusion.
(1 point)
The p-value is 0.99952. Since the p-value is greater than the significance level, Robert fails to reject the null
hypothesis. This suggests that the proportion of subscribers in Virginia who watched the documentary is
0.4.
The p-value is 0.00096. Since the p-value is greater than the significance level, Robert rejects the null
hypothesis. This suggests that the proportion of subscribers in Virginia who watched the documentary is
greater than 0.4.
The p-value is 0.00048. Since the p-value is less than the significance level, Robert rejects the null
hypothesis. This suggests that the proportion of subscribers in Virginia who watched the documentary is
greater than 0.4.
The p-value is 0.00062. Since the p-value is less than the significance level, Robert rejects the null
hypothesis. This suggests that the proportion of subscribers in Virginia who watched the documentary is
greater than 0.4.

Answer 1

The p-value is 0.00062. Since the p-value is less than the significance level, Robert rejects the null hypothesis. This suggests that the proportion of subscribers in Virginia who watched the documentary is greater than 0.4.