Asked by Destiny Padgett
How would you go about answering this?
If x and y are both positive evaluate
A.) lim= (ln(0.8x^p+2.0y^p))/p
p->0
B.) lim= (0.8x^p+2.0y^p)^(1/p)
p->0
If x and y are both positive evaluate
A.) lim= (ln(0.8x^p+2.0y^p))/p
p->0
B.) lim= (0.8x^p+2.0y^p)^(1/p)
p->0
Answers
Answered by
oobleck
I don't think the limit exists. Consider the case where y=0. Then
ln(0.8x^p)/p = (ln0.8 + p*lnx)/p = ln0.8/p + lnx
As p→0, lnx→-∞ and 0.8/p→∞
And if y is not zero, then you have yet another number divided by p, which will also be undefined.
ln(0.8x^p)/p = (ln0.8 + p*lnx)/p = ln0.8/p + lnx
As p→0, lnx→-∞ and 0.8/p→∞
And if y is not zero, then you have yet another number divided by p, which will also be undefined.
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