To find the probability that a shopper preferred neither drink E nor drink C, we need to add up the number of shoppers who preferred either drink A, B, or D.
From the table, we see that there were 8 shoppers who preferred drink A, 11 who preferred drink B, and 14 who preferred drink D.
So the total number of shoppers who did not prefer drink E or drink C is:
8 + 11 + 14 = 33
Out of the 41 shoppers total, the probability of selecting one who preferred neither drink E nor drink C is:
33/41
Therefore, the answer is A. 35/41.
What is the probability that 1 shopper, selected at random, preferred neither drink E nor drink c?
A. 35/41
B. 13/41
C. 28/41
D. 13/28
2 answers
To determine the probability that a shopper prefers neither drink E nor drink C, we first need to know the total number of shoppers and the number of shoppers that prefer each drink. Unfortunately, based on the information provided there isn't enough information to answer this question. We need the total number of shoppers and the number of shoppers that prefer each drink to calculate the probability.