Let's call the unknown number "x".
According to the problem:
3/4 x + 3 1/3 = 6 1/2 - 2/3 x
First, let's simplify the fractions:
3/4 x + 10/3 = 13/2 - 2/3 x
Next, let's get rid of the fractions by multiplying everything by the least common multiple of 3 and 4, which is 12:
9x + 40 = 78 - 8x
Now, let's isolate x by adding 8x to both sides and subtracting 40 from both sides:
17x = 38
Finally, we can solve for x by dividing both sides by 17:
x = 38/17
Therefore, the number we were looking for is 38/17.
Find the number such that when 3/4 of it is added to 3 1/3, the sum is the same as when 2/3 if it is subtracted from 6 1/2
1 answer