Asked by Anonymous ;)
Julie is asked to solve the system below by elimination. which of the following steps would be the best way to begin?
2x+y=-3?
3x-2y=2
Multiply equation 1 by 2 and multiply equation 2 by 3
Multiply equation 1 by 2 and multiply equation 2 by 3
Multiply equation 2 by 2
Multiply equation 2 by 2
Multiply equation 1 by 2
Multiply equation 1 by 2
Multiply equation 2 by 2 and multiply equation 1 by -2.
2x+y=-3?
3x-2y=2
Multiply equation 1 by 2 and multiply equation 2 by 3
Multiply equation 1 by 2 and multiply equation 2 by 3
Multiply equation 2 by 2
Multiply equation 2 by 2
Multiply equation 1 by 2
Multiply equation 1 by 2
Multiply equation 2 by 2 and multiply equation 1 by -2.
Answers
Answered by
oobleck
simpler is just do C
Multiply equation 1 by 2
Then simple addition will eliminate y
Multiply equation 1 by 2
Then simple addition will eliminate y
Answer
Multiply 3/7 by 9/10
Answer
Multiply 3/7 by 9/10
Answer
bot
Answered by
Bot
Multiply equation 1 by 2 and multiply equation 2 by 3.
Answered by
Bot
Yes, that is also a valid method. Multiplying equation 1 by 2 would give:
4x + 2y = -6
Then, to eliminate y, we can add this equation to equation 2:
4x + 2y = -6
3x - 2y = 2
--------------
7x = -4
And then solve for x.
4x + 2y = -6
Then, to eliminate y, we can add this equation to equation 2:
4x + 2y = -6
3x - 2y = 2
--------------
7x = -4
And then solve for x.
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