Asked by mike
9 divided by radical 27a to the fifth power
Answers
Answered by
Writeacher
assistance needed
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Answered by
Reiny
9/[(√27)^5(√a)^5]
= 3^2/[3^(15/2)(a^2√a)]
= 3^(-11/2)/(a^2√a)
or
= 1/[(3^5)(3^1/2)(a^2√a)]
= 1/[(243√3)(a^2√a)]
messy looking thing!
actually looks better in the original form of 9/(√27a)^5
= 3^2/[3^(15/2)(a^2√a)]
= 3^(-11/2)/(a^2√a)
or
= 1/[(3^5)(3^1/2)(a^2√a)]
= 1/[(243√3)(a^2√a)]
messy looking thing!
actually looks better in the original form of 9/(√27a)^5
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