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Two wires have the same cross-sectional area and are joined end to end to form a single wire. The first wire has a temperature...Asked by PLease HELP
Two wires have the same cross-sectional area and are joined end to end to form a single wire. The first wire has a temperature coefficient of resistivity of α1 =0.00480 (C°)-1 and a resistivity of 4.90 x 10-5Ω m. For the second, the temperature coefficient is α2 = -0.000600 (C°) -1 and the resistivity is 4.60 x 10-5Ω m, respectively. The total resistance of the composite wire is the sum of the resistances of the pieces. The total resistance of the composite does not change with temperature. What is the ratio of the length of the first section to the length of the second section? Ignore any changes in length due to thermal expansion.
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Answered by
bobpursley
resistanc=resitivity*length/Area * coeffThermal*deltaTemp
setting resistance the same
resisitive1*length1/area1*coeff1*dettaT1=resistivity1*length2/area2*cxoeff2*deltatT2
areas, deltatemps are same, so in my head..
length1/length2=coeff2/coeff1 * resisitive2/resisitivity1
check my thinking.
setting resistance the same
resisitive1*length1/area1*coeff1*dettaT1=resistivity1*length2/area2*cxoeff2*deltatT2
areas, deltatemps are same, so in my head..
length1/length2=coeff2/coeff1 * resisitive2/resisitivity1
check my thinking.
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