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AnonymousUser1234
anyone gonna answer this?
Answered by
AnonymousUser1234
Show all the steps that you use to solve this problem in the space provided.
An image of a rocket is shown. The rocket is made up of a triangle, a rectangle, and a trapezoid. The triangle at the top of the rocket has a base of length 3 inches and a height of 4 inches. The rectangle in the middle of the rocket has a height of 10 inches and a length of 3 inches. The trapezoid at the bottom of the rocket has one base of length 3 inches at the top, another base of length 5 inches at the bottom, and a height of 2 inches.
An image of a rocket is shown. The rocket is made up of a triangle, a rectangle, and a trapezoid. The triangle at the top of the rocket has a base of length 3 inches and a height of 4 inches. The rectangle in the middle of the rocket has a height of 10 inches and a length of 3 inches. The trapezoid at the bottom of the rocket has one base of length 3 inches at the top, another base of length 5 inches at the bottom, and a height of 2 inches.
Answered by
AnonymousUser1234
An image of a rocket is shown. The rocket is made up of a triangle, a rectangle, and a trapezoid. The triangle at the top of the rocket has a base of length 3 inches and a height of 4 inches. The rectangle in the middle of the rocket has a height of 10 inches and a length of 3 inches. The trapezoid at the bottom of the rocket has one base of length 3 inches at the top, another base of length 5 inches at the bottom, and a height of 2 inches.
Use familiar figures to find the area of the figure shown.
Use familiar figures to find the area of the figure shown.
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Bot
I'm sorry, I am an AI language model and I do not know the specific question you are referring to. Please provide me with more information so I can better assist you.
Answered by
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In order to find the area of the rocket, we need to find the area of each individual shape and then add them together.
1. Area of the triangle = (base x height)/2 = (3 x 4)/2 = 6 square inches
2. Area of the rectangle = length x width = 3 x 10 = 30 square inches
3. Area of the trapezoid = [(base 1 + base 2) x height] / 2 = [(3 + 5) x 2] / 2 = 8 square inches
Now we can add the areas together to find the total area of the rocket:
Total area = 6 + 30 + 8 = 44 square inches.
Therefore, the area of the rocket is 44 square inches.
1. Area of the triangle = (base x height)/2 = (3 x 4)/2 = 6 square inches
2. Area of the rectangle = length x width = 3 x 10 = 30 square inches
3. Area of the trapezoid = [(base 1 + base 2) x height] / 2 = [(3 + 5) x 2] / 2 = 8 square inches
Now we can add the areas together to find the total area of the rocket:
Total area = 6 + 30 + 8 = 44 square inches.
Therefore, the area of the rocket is 44 square inches.
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