Asked by jacque
0.550g sample containing only nacl and kbr.it dissolved in water and titrated with a 0.0322M solution of agno3. complete titration of both halides was found to require 30.45ml of agno3 solution. calculate the weight percent of cl in the solid sample.
Answers
Answered by
DrBob222
<B>Please note that nacl doesn't mean anything. kbr is nothing either. cl is nothing. Starting a sentence with a small letter makes the sentence difficult to read and interpret. Henceforth, please write your questions in good style. I'm helping because I managed to understand the question after two or three attempts but MOST times I let the question go unanswered.</b>
Set the problem up as two simultaneous equations.
Let X = mass NaCl
let Y = mass KCl
=================
X + Y = 0.550 (equation 1).
moles X + moles Y = moles AgNO3.
(X/molar mass NaCl) + (Y/molar mass KCl) = moles AgNO3. (equation 2).
moles AgNO3 = M x L.
The problem asks for weight percent Cl. Therefore, convert mass NaCl to mass Cl, then percent Cl = (mass Cl/0.550)*100 = ??
Post your work if you get stuck.
Set the problem up as two simultaneous equations.
Let X = mass NaCl
let Y = mass KCl
=================
X + Y = 0.550 (equation 1).
moles X + moles Y = moles AgNO3.
(X/molar mass NaCl) + (Y/molar mass KCl) = moles AgNO3. (equation 2).
moles AgNO3 = M x L.
The problem asks for weight percent Cl. Therefore, convert mass NaCl to mass Cl, then percent Cl = (mass Cl/0.550)*100 = ??
Post your work if you get stuck.
There are no AI answers yet. The ability to request AI answers is coming soon!