The correct answer is 35.9 J.
Using the kinetic energy formula KE=1/2mv^2, we can calculate the kinetic energies of the bowling ball at each speed:
At 16 mph: KE = 1/2 * 6 kg * (7.1 m/s)^2 = 151.2 J
At 14 mph: KE = 1/2 * 6 kg * (6.2 m/s)^2 = 115.3 J
The difference between these two energies is:
KE difference = 151.2 J - 115.3 J = 35.9 J
Therefore, the bowling ball has 35.9 J more kinetic energy when rolling at 16 mph than at 14 mph.
How much more kinetic energy does a 6-kilogram bowling ball have when it is rolling at 16 mph (7.1 meters per second) than when it is rolling at 14 mph (6.2 meters per second)?
KE=12mv2
(1 point)
Responses
151.2 J
151.2 J
35.9 J
35.9 J
1.3 J
1.3 J
266.5 J
266.5 J
1 answer