Question
A ball is thrown into the air with an initial upward velocity of 48 ft/s. Its height (h) in feet after t seconds is given by the function \large h=-16t^2+48t+64. After how many seconds will the ball hit the ground?
Responses
5 seconds
5 seconds
7 seconds
7 seconds
4 seconds
4 seconds
6 seconds
Responses
5 seconds
5 seconds
7 seconds
7 seconds
4 seconds
4 seconds
6 seconds
Answers
6 seconds
Related Questions
A ball is thrown into the air with an initial upward velocity of 48ft/s its height h in feet after t...
A ball is thrown into the air with an initial upward velocity of 46 ft/s. Its height (h) in feet aft...
A ball is thrown into the air with an initial upward velocity of 46 ft/s. Its height (h) in feet aft...