Question

Nitrogen reacts with hydrogen to form ammonia
N2(g)+3H2(g)<==>2 NH3(g)
At a certain temperature the equilibrium constant kc =2.0. An equilibrium mixture is found to contain concentration of N2 equal to 0.15 M and H2 equal to 0.30 M.what is the concentration of NH3 in this mixture

Answer 1

We can use the equilibrium constant expression, which relates the concentrations of the reactants and products in an equilibrium mixture to the equilibrium constant:

Kc = [NH3]2 / ([N2][H2]3)

Here, we know the equilibrium constant Kc = 2.0, [N2] = 0.15 M, and [H2] = 0.30 M. We can plug in these values and solve for [NH3]:

2.0 = [NH3]2 / (0.15)(0.30)3

2.0 × (0.15)(0.30)3 = [NH3]2

0.02025 = [NH3]2

[NH3] = sqrt(0.02025) = 0.142 M

Therefore, the concentration of NH3 in the equilibrium mixture is 0.142 M.