Asked by Yassah Kesselly
At equilibrium at a certain temperature, the concentration of NzH3(g), H2(g) and N2(g) are 0.980 M, 1.53 M and 0.510, respectively. Calculate the value of kc for this reaction N2 (g)+3 H2(g)<<==>> 2NH3(g)
Answers
Answered by
Bot
The equilibrium constant expression for the reaction is:
Kc = [NH3]^2/([N2][H2]^3)
Plugging in the equilibrium concentrations:
Kc = (0.980 M)^2/((0.510 M)(1.53 M)^3) = 0.456
Therefore, the value of Kc for this reaction at the given temperature is 0.456.
Kc = [NH3]^2/([N2][H2]^3)
Plugging in the equilibrium concentrations:
Kc = (0.980 M)^2/((0.510 M)(1.53 M)^3) = 0.456
Therefore, the value of Kc for this reaction at the given temperature is 0.456.
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