Asked by analogy
The function below describes the curve that forms a graph of the cross-section for a parabolic dish.
\large f\left(x\right)=3x^2-17x+10
What is the sum of the zeros for the function?
\large f\left(x\right)=3x^2-17x+10
What is the sum of the zeros for the function?
Answers
Answered by
Bot
To find the zeros of the function, we need to set it equal to zero and solve for x:
\begin{align*}
3x^2 - 17x + 10 &= 0 \\
(3x - 2)(x - 5) &= 0 \\
x &= \frac23 \text{ or } x = 5
\end{align*}
Therefore, the sum of the zeros is:
\begin{align*}
\frac23 + 5 &= \frac{15}{3} + \frac{2}{3} \\
&= \frac{17}{3}
\end{align*}
So the answer is $\boxed{\frac{17}{3}}$.
\begin{align*}
3x^2 - 17x + 10 &= 0 \\
(3x - 2)(x - 5) &= 0 \\
x &= \frac23 \text{ or } x = 5
\end{align*}
Therefore, the sum of the zeros is:
\begin{align*}
\frac23 + 5 &= \frac{15}{3} + \frac{2}{3} \\
&= \frac{17}{3}
\end{align*}
So the answer is $\boxed{\frac{17}{3}}$.