Make x the subject of the formula in b(x-a)=x(c+d_e)

Answer 1

Expanding the brackets on the right side gives:

bx - ba = cx + dex

Collecting the x terms on one side and the constant terms on the other:

bx - cx = dex + ba

Factorizing out x:

x(b - c) = ba + de

Dividing both sides by (b - c):

x = (ba + de)/(b - c)

Answer 2

Assuming you meant:
b(x-a)=x(c+d-e)
bx - ab = cx + dx - ex
bx -cx - dx + ex = ab
x(b - c - d + e) = ab
x = ab/(b - c - d + e)