Asked by Ametel
A car travels north at 30.0 m/s for 10.0 min. It then travels south at 40.0 m/s for 20.0
min. What are the total distance the car travels and its displacement?
min. What are the total distance the car travels and its displacement?
Answers
Answered by
Damon
distance north = 30 m/s * 10 min * 60 s/min = 18000 meters north
south = 40 *20 * 60 = 48000 meters south
distance = 18 kilometers + 48 km = 66 km = 66,000 meters
displacement = 48 - 18 = 30 Km = 30,000 meters SOUTH
south = 40 *20 * 60 = 48000 meters south
distance = 18 kilometers + 48 km = 66 km = 66,000 meters
displacement = 48 - 18 = 30 Km = 30,000 meters SOUTH
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