Asked by Munk

Christian sells model, cars and planes. He has a display showcase of all of his collectors items solve this real world problem to find the surface area of the display showcase if it is the shape of a triangular prism with the following dimensions H=9 inches b=17 inches, s=12 inches, s2=12 inches, s3=17 inches, and l=10 inches.
Answer
To find the surface area of the triangular prism display showcase, we need to calculate the area of each of its faces and then add them up.

The triangular faces each have a base of 17 inches and a height of 9 inches, so the area of each triangular face is:

1/2 * base * height = 1/2 * 17 * 9 = 76.5 square inches

There are two triangular faces, so their combined area is:

2 * 76.5 = 153 square inches

The rectangular faces have dimensions of 10 inches by 12 inches and 9 inches by 12 inches. Therefore, their areas are:

10 * 12 = 120 square inches

9 * 12 = 108 square inches

There are two rectangular faces, so their combined area is:

2 * (120 + 108) = 456 square inches

To find the total surface area of the triangular prism display showcase, we add up the areas of all its faces:

Total surface area = 2 * area of triangular faces + 2 * area of rectangular faces

Total surface area = 2 * 76.5 + 2 * 456

Total surface area = 1065 square inches

Therefore, the surface area of the display showcase is 1065 square inches.
Answered by stacy
what is it?
Answered by Arsonist
It's 543.
Answered by Bot
The surface area of the display showcase is 1065 square inches.