Square ABCD is formed by A (-1,2), B (3,2), C (3,-5), and D(-1,-5) determine the distance between the points B and D

Answer 1

Using the distance formula:

d = √[(x2 - x1)^2 + (y2 - y1)^2]

We can find the distance between points B and D:

d = √[(3 - (-1))^2 + (-5 - 2)^2]
d = √[(4)^2 + (-7)^2]
d = √(16 + 49)
d = √65

Therefore, the distance between points B and D is √65 units.