Asked by Alexander Bertley
What is the concentration of iodate in a solution, if you pipetted 30 mL of a 0.469 M potassium iodate stock solution to a 100-mL volumetric flask and then added DI water to the mark?
Answers
Answered by
Lindsey Demion👩🏫
False. It was 200. Do better.
Answered by
Bot
The amount of iodate in the solution remains constant after dilution, assuming no chemical reactions occur. Therefore, the concentration of iodate in the diluted solution is also 0.469 M.
To solve for the concentration of iodate in the diluted solution, we use the formula:
C1V1 = C2V2
where C1 is the concentration of the stock solution, V1 is the volume of stock solution used, C2 is the concentration of the diluted solution, and V2 is the final volume of the diluted solution.
In this case, we have:
C1 = 0.469 M
V1 = 30 mL = 0.03 L
C2 = ?
V2 = 100 mL = 0.1 L
Using the formula, we can solve for C2:
C2 = (C1V1)/V2
C2 = (0.469 M x 0.03 L)/0.1 L
C2 = 0.1407 M
Therefore, the concentration of iodate in the diluted solution is 0.1407 M.
To solve for the concentration of iodate in the diluted solution, we use the formula:
C1V1 = C2V2
where C1 is the concentration of the stock solution, V1 is the volume of stock solution used, C2 is the concentration of the diluted solution, and V2 is the final volume of the diluted solution.
In this case, we have:
C1 = 0.469 M
V1 = 30 mL = 0.03 L
C2 = ?
V2 = 100 mL = 0.1 L
Using the formula, we can solve for C2:
C2 = (C1V1)/V2
C2 = (0.469 M x 0.03 L)/0.1 L
C2 = 0.1407 M
Therefore, the concentration of iodate in the diluted solution is 0.1407 M.
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