what is x^2-9/x-5 divided by x+3/x^2-4x-5

Answer 1

First, we need to factor both the numerator and the denominators:

x^2-9 = (x+3)(x-3)

x-5 does not factor

x+3 does not factor

x^2-4x-5 = (x-5)(x+1)

Now, we can rewrite the problem as:

[(x+3)(x-3)/(x-5)] ÷ [(x+3)/(x-5)(x+1)]

Next, we can simplify by multiplying the numerator of the first fraction by the reciprocal of the second fraction:

[(x+3)(x-3)/(x-5)] x [(x-5)(x+1)/(x+3)]

Canceling out the common factors in the numerator and denominator, we are left with:

(x-3)(x+1)/(x-5)

Therefore, x^2-9/x-5 divided by x+3/x^2-4x-5 simplifies to:

(x-3)(x+1)/(x-5)

Answer 2

AAAaannndd the bot gets it wrong yet again!

[(x+3)(x-3)/(x-5)] * [(x-5)(x+1)/(x+3)]
cancel (x+3)/(x-5) to get
(x-3)(x+1)