Given that, s=n/2 [2a + (n -1)d ], a=3, d = 4 and n = 10, find the value of s.

Answer 1

Substitute the given values into the formula:

s = n/2 [2a + (n -1)d]
s = 10/2 [2(3) + (10 - 1)(4)]
s = 5 [6 + 36]
s = 5 x 42
s = 210

Therefore, the value of s is 210.