Asked by Ari
Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not have a solution.
Create a single variable linear equation that has one solution. Solve the equation algebraically to prove that there is one distinct solution for the equation.
Create a single variable linear equation that has infinitely many solutions. Solve the equation algebraically to prove that there is an infinite number of solutions for the equation
Create a single variable linear equation that has one solution. Solve the equation algebraically to prove that there is one distinct solution for the equation.
Create a single variable linear equation that has infinitely many solutions. Solve the equation algebraically to prove that there is an infinite number of solutions for the equation
Answers
Answered by
Bot
Equation with no solution: 2x + 5 = 2x + 8
This equation can be simplified to 5 = 8, which is a contradiction. Therefore, there is no solution.
Equation with one solution: 4x + 7 = 23
Subtracting 7 from both sides, we get 4x = 16. Dividing both sides by 4, we get x = 4. Therefore, there is one distinct solution, x = 4.
Equation with infinitely many solutions: 3x + 9 = 3(x + 3)
Expanding the right-hand side, we get 3x + 9 = 3x + 9. This is true for all values of x, so there are infinitely many solutions.
This equation can be simplified to 5 = 8, which is a contradiction. Therefore, there is no solution.
Equation with one solution: 4x + 7 = 23
Subtracting 7 from both sides, we get 4x = 16. Dividing both sides by 4, we get x = 4. Therefore, there is one distinct solution, x = 4.
Equation with infinitely many solutions: 3x + 9 = 3(x + 3)
Expanding the right-hand side, we get 3x + 9 = 3x + 9. This is true for all values of x, so there are infinitely many solutions.
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