2moles of NH3 are enclosed in a 20cm^3 vessel at 27 degree celsius. Calculate the pressure exerted by the gas

Answer 1

The ideal gas law (PV = nRT) can be used to solve for pressure (P) when given the number of moles (n), volume (V), and temperature (T) of a gas.

First, convert the volume to liters:

20 cm^3 = 0.02 L

Next, convert the temperature to Kelvin:

27°C + 273 = 300 K

The molar mass of ammonia (NH3) is 17 g/mol, so 2 moles of NH3 have a mass of:

2 mol NH3 x 17 g/mol = 34 g NH3

Using the ideal gas law, we can solve for pressure:

PV = nRT

P = nRT/V

P = (2 mol x 0.0821 L∙atm/mol∙K x 300 K) / 0.02 L

P = 123.15 atm

Therefore, the pressure exerted by the gas is 123.15 atm.