Asked by Sinachi
A balloon that contains 1.5l of air at 1atm is taken under water to a depth at which the pressure is 2.5atm. Calculate the new volume of the balloon if temperature remains constant
Answers
Answered by
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We can use Boyle's law to solve this problem:
P1V1 = P2V2
Where P1 is the initial pressure (1 atm), V1 is the initial volume (1.5 L), P2 is the final pressure (2.5 atm), and V2 is the final volume (which we want to find). Since the temperature remains constant, we can assume that the amount of gas in the balloon remains the same.
Substituting the values we know:
(1 atm)(1.5 L) = (2.5 atm)(V2)
Simplifying:
V2 = (1 atm)(1.5 L) / (2.5 atm) = 0.9 L
So the new volume of the balloon is 0.9 L.
P1V1 = P2V2
Where P1 is the initial pressure (1 atm), V1 is the initial volume (1.5 L), P2 is the final pressure (2.5 atm), and V2 is the final volume (which we want to find). Since the temperature remains constant, we can assume that the amount of gas in the balloon remains the same.
Substituting the values we know:
(1 atm)(1.5 L) = (2.5 atm)(V2)
Simplifying:
V2 = (1 atm)(1.5 L) / (2.5 atm) = 0.9 L
So the new volume of the balloon is 0.9 L.
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