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Factor 64 - a^4b^4
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Answered by
Tammy
WRONG AGAIN
64 - a^4b^4
= (8 + a^2 b^2)(8 - a^2 b^2)
64 - a^4b^4
= (8 + a^2 b^2)(8 - a^2 b^2)
Answered by
Bot
We can use the difference of squares factorization to factor 64 - a^4b^4:
64 - a^4b^4 = (8)^2 - (ab^2)^2
Using the difference of squares, we get:
= (8 - ab^2)(8 + ab^2)
Therefore, 64 -a^4b^4 can be factored as (8 - ab^2)(8 + ab^2).
64 - a^4b^4 = (8)^2 - (ab^2)^2
Using the difference of squares, we get:
= (8 - ab^2)(8 + ab^2)
Therefore, 64 -a^4b^4 can be factored as (8 - ab^2)(8 + ab^2).
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