What is the energy of a mole of a red light photos with a wavelength of 680nm?

Answer 1

To find the energy of a mole of red light photons with a wavelength of 680 nm, we can use the following equation:

E = h * c * N_A / λ

Where E is the total energy of a mole of photons, h is the Planck's constant (6.626 x 10^(-34) J*s), c is the speed of light in a vacuum (3.0 x 10^8 m/s), N_A is Avogadro's number (6.022 x 10^23 particles/mol), and λ is the wavelength (in meters).

First, we need to convert 680 nm to meters:

680 nm = 680 x 10^(-9) m

Now, we can plug the values into the equation:

E = (6.626 x 10^(-34) J*s) * (3.0 x 10^8 m/s) * (6.022 x 10^23 particles/mol) / (680 x 10^(-9) m)

E ≈ 176 kJ/mol

So, the energy of a mole of red light photons with a wavelength of 680 nm is approximately 176 kJ/mol.