The energy (E) of a photon of radio wave is given by the Planck's equation:
E = h x f
Where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of the wave.
Therefore, for a radio wave photon with a frequency of 909 kHz (909,000 Hz):
E = 6.626 x 10^-34 J*s x 909,000 Hz
E = 6.02 x 10^-26 J
So, the energy of a single radio wave photon with a frequency of 909 kHz is 6.02 x 10^-26 J. However, the energy of a mile of radio wave photons with this frequency will depend on the intensity (amplitude) of the wave and the number of photons present.
What is the energy of a mile of radio wave photons with a frequency of 909kHz?
1 answer