A local college wants to determine student interest in athletics and in academic clubs. The college surveys a random group of students, and the results of the survey are described below.
A total of 240 students were included in the survey.
Thirty-five percent of the students were interested in athletics.
Three-fifths of the students were interested in academic clubs.
A total of 26 students were interested in both athletics and academic clubs.
Complete the two-way table below to represent the survey results by filling in each of the 9 cells with an appropriate number of students.
Interested in Athletics NOT Interested in Athletics Total
Interested in Academic Clubs 1 2 3
Not Interested in Academic Clubs 4 5 6
Total 7 8 9
Word Bank:
58 156 118 26 144 38 84 96 240
Blank 1:
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Blank 9:
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Blank 2: 26
Blank 3: 110
Blank 4: 30
Blank 5: 144
Blank 6: 106
Blank 7: 118
Blank 8: 150
Blank 9: 240
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1. From the problem statement, we know that 35% of the 240 students were interested in athletics. Therefore, there were 0.35 x 240 = 84 students who were interested in athletics.
2. We also know that 3/5 of the students were interested in academic clubs. So, there were 3/5 x 240 = 144 students who were interested in academic clubs.
3. The problem tells us that 26 students were interested in both athletics and academic clubs, so we can fill in that number in the cell where the two categories intersect.
4. To fill in the remaining cells, we can subtract the number of students already accounted for from the total number of students surveyed (240). For example, to find the number of students who are interested in athletics but not academic clubs, we can subtract the number who are interested in both from the total who are interested in athletics: 84 - 26 = 58. This number goes in the cell where "Interested in Athletics" and "Not Interested in Academic Clubs" intersect.
5. By following similar steps for the other cells, we can fill in the entire table as shown in the answer above.
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However, I can tell you that, in general, when you multiply a number that has only 1s by any number, the result will have the same number of digits as the original number, and all the digits will be the number you are multiplying by, except for the rightmost digit, which may be different.
For example, if we take the number 111111111 and multiply it by 2, we get 222222222, which has the same number of digits as the original number and all the digits are 2 except for the rightmost digit.
But, the number you provided is very large and it's not practical to write out the result.
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Your Highness!
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Acad. 26 | 118 = 144
No Acad. 58 | 38 = 96
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Totals 84 | 156 = 240
Ya Welcome!
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