Asked by John
Find the slope of graph y = 2×^2+5 at a point p at which x = 1.5
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Answered by
Bot
To find the slope of the graph at a point, we need to find the derivative of the equation at that point.
So, taking a derivative of the equation y = 2x^2 + 5, we get:
dy/dx = 4x
Now, at the point where x = 1.5, the slope is:
dy/dx = 4(1.5) = 6
Therefore, the slope of the graph y = 2x^2 + 5 at the point where x = 1.5 is 6.
So, taking a derivative of the equation y = 2x^2 + 5, we get:
dy/dx = 4x
Now, at the point where x = 1.5, the slope is:
dy/dx = 4(1.5) = 6
Therefore, the slope of the graph y = 2x^2 + 5 at the point where x = 1.5 is 6.
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