(b-6)(b+3)
use FOIL:
b*b
b*3
-6*b
-6*3
add them together to get:
b^2 - 3b - 18
(b-6)*(b+3)
use FOIL:
b*b
b*3
-6*b
-6*3
add them together to get:
b^2 - 3b - 18
When you have equations like this you should pretend there are no brackets around the first equation.
b-6 (b+3)
first you distribute b into the brackets.
(b)(b) = b^2
then b to 3
(b)(3) = 3b
then you distribute the -6 to both...
(-6)(b) = -6b
then -6 to 3...
(-6)(3) = -18
then you add them together...
b^2-3b-18
:)
Here's how to do it step by step:
1. Start by multiplying the first terms of each binomial together. In this case, we multiply 'b' from the first binomial and 'b' from the second binomial. The result is b^2.
2. Next, multiply the first term from the first binomial with the second term from the second binomial. In this case, multiplying 'b' from the first binomial with '3' from the second binomial gives us 3b.
3. Then, multiply the second term from the first binomial with the first term from the second binomial. In this case, multiplying '-6' from the first binomial with 'b' from the second binomial gives us -6b.
4. Finally, multiply the second terms of each binomial together. In this case, multiplying '-6' from the first binomial with '3' from the second binomial gives us -18.
5. Now, combine the products obtained in steps 1, 2, 3, and 4. We have b^2 + 3b - 6b - 18.
6. Simplify the expression by combining like terms. In this case, combining '3b' and '-6b' gives us -3b.
7. The final result is b^2 - 3b - 18.
Therefore, (b-6)*(b+3) equals b^2 - 3b - 18.