Asked by Mamabear
Trapezoids and Kites quiz part 2
answered 2023
1. Find the values of the variables and the lengths of the sides of the kites: y-4, x+5,2x+5,x+12
Ab=cd
Ad=cd
2x+5=x+12
2x-x=12-5
which means
2x+5=x+12
2x-x=12-5
X=7
Now x=5=7-4
7+5=y-4
12+4=y
Y=16
means that
y-4=16-4=12
X+5=7+5=12
2x+5=2x+7+5=19
X+12=7+12=19
Answer 12 & 19
2. Find m angle 1 and m angle 3 in the kite 39 degrees given
Angle 1 =corresponding angle which means that angle 1=39 degrees
Given 39 degrees and a 90 degree angle
Angle 3 =180-(39+90)
180-129=51
Angle3=51
3. Line LM is midsegment of trapezoid ABCD, if AB=48 and DC= 125 what is LM
Use the following to solve:
AB+DC/2 LM=85.5
4. Find the values of a and b in the quadrilateral 144° and 67° are given
From the given figure, we get
a°+36°=180°(Angles on the same side)
a°=180°-36°a°=144°.
Now, Sum of all the angles of a quadrilateral= 360°
Therefore, a°+36°+b°+113°=360°
144°+36°+b°+113°=360°
b°+293°=360°
b°=360-293
b°=67°
Therefore, values of a and b are 144° and 67°.
5. in rectangle KLMN KM=6x+16 LN=49
KM=LN
6x+16=49
6x=49-16
6x=33
x=33/6
x=11/2
x=5.5
6. In the rhombus m angle 1=18x, m angle 2=x+y, and m angle3=30z find the variables
Rhombus => angle 1= angle 2= angle 3 =90
18x=90
90/18=5
x=5
x-y=90
90-5=85
Y=85
Z=90/30
90/30=3
Z=3
answered 2023
1. Find the values of the variables and the lengths of the sides of the kites: y-4, x+5,2x+5,x+12
Ab=cd
Ad=cd
2x+5=x+12
2x-x=12-5
which means
2x+5=x+12
2x-x=12-5
X=7
Now x=5=7-4
7+5=y-4
12+4=y
Y=16
means that
y-4=16-4=12
X+5=7+5=12
2x+5=2x+7+5=19
X+12=7+12=19
Answer 12 & 19
2. Find m angle 1 and m angle 3 in the kite 39 degrees given
Angle 1 =corresponding angle which means that angle 1=39 degrees
Given 39 degrees and a 90 degree angle
Angle 3 =180-(39+90)
180-129=51
Angle3=51
3. Line LM is midsegment of trapezoid ABCD, if AB=48 and DC= 125 what is LM
Use the following to solve:
AB+DC/2 LM=85.5
4. Find the values of a and b in the quadrilateral 144° and 67° are given
From the given figure, we get
a°+36°=180°(Angles on the same side)
a°=180°-36°a°=144°.
Now, Sum of all the angles of a quadrilateral= 360°
Therefore, a°+36°+b°+113°=360°
144°+36°+b°+113°=360°
b°+293°=360°
b°=360-293
b°=67°
Therefore, values of a and b are 144° and 67°.
5. in rectangle KLMN KM=6x+16 LN=49
KM=LN
6x+16=49
6x=49-16
6x=33
x=33/6
x=11/2
x=5.5
6. In the rhombus m angle 1=18x, m angle 2=x+y, and m angle3=30z find the variables
Rhombus => angle 1= angle 2= angle 3 =90
18x=90
90/18=5
x=5
x-y=90
90-5=85
Y=85
Z=90/30
90/30=3
Z=3
Answers
Answered by
Mamabear
Thanks!
Answered by
Tammy
#3
(48+125)/2 = 86.5 , not 85.5
#4 , the bot's answer is right only if you have a rectangle.
It did not say that, it said it was a quadrilateral, so the AI made an assumption.
#6
by saying 18x = 90 , the bot assumed your rhombus was a square.
Invalid assumption.
(48+125)/2 = 86.5 , not 85.5
#4 , the bot's answer is right only if you have a rectangle.
It did not say that, it said it was a quadrilateral, so the AI made an assumption.
#6
by saying 18x = 90 , the bot assumed your rhombus was a square.
Invalid assumption.
Answered by
Mamabear
@Tammy thanks
Answered by
Mamabear
Submitted and graded recieved 100% :)
Answered by
Bot
Great job, all of your answers are correct! Let me know if you have any other questions.
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