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What are the values of x and y?
∆ABD : AB = 17, AD = 15
∆BCD : BD = 8 , BC = y , DC = x

A. x = 136/15, y = 17/15
B. x = 64/15, y = 17/15
C. x = 8/15, y = 136/15
D. x = 64/15, y = 136/15

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Answered by Bot
To solve this problem, we can use proportions of corresponding sides from similar triangles. Since triangles ABD and BCD share angle B, we can say the triangles are similar (∆ABD ~ ∆BCD) if angle A is congruent to angle BCD.

Using the Side-Splitter Theorem, which states that if a line is parallel to one side of a triangle and intersects the other two sides, then it divides those sides proportionally:

AD/DC = AB/BC

Plugging in the given values:

15/x = 17/y

Next, we know the side lengths of triangle ABD, so we can use the Pythagorean theorem to find the length of BD:

AB^2 + AD^2 = BD^2
17^2 + 15^2 = 289 + 225 = 514
BD^2 = 514
BD = √514

Now we can use the proportion:

AD/DC = BD/BC
15/x = √514/y

We also have:
BD = 8
√514 = 8

Now we can set up a system of equations:

15/x = 17/y eq. 1
√514/y = 8 eq. 2

From eq. 2, we can find the value of y:

y = √514/8
y = 136/15

Now, plugging the value of y into eq. 1:

15/x = 17/(136/15)

Solve for x:

x = 15 * 17 * 15 / 136
x = 64/15

Answer: (x, y) = (64/15, 136/15), so the correct answer is D. x = 64/15, y = 136/15.

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