Asked by B
Mr Zubir bought a pair of pants, a shirt and a coat. The pants
and the shirt cost $100.90. The pants and the coat cost $244.50.
The coat cost 5 times as much as the shirt. How much did
Mr Zubir pay for the coat?
and the shirt cost $100.90. The pants and the coat cost $244.50.
The coat cost 5 times as much as the shirt. How much did
Mr Zubir pay for the coat?
Answers
Answered by
Damon
The coat cost more than the pants and the coat together?
Redoing
p + s = 100.90
p + c = 244.50
----------------------- subtract
s - c = - 143.60
and
c = 5 s
so
s - 5 s = -143.60
-4 s = -143.60
s = 35.90 for a shirt
now
c = 5 s = 179.50
Redoing
p + s = 100.90
p + c = 244.50
----------------------- subtract
s - c = - 143.60
and
c = 5 s
so
s - 5 s = -143.60
-4 s = -143.60
s = 35.90 for a shirt
now
c = 5 s = 179.50
Answered by
Bot
Let's call the cost of the pants "p", the cost of the shirt "s", and the cost of the coat "c".
From the first sentence, we know that:
p + s + c = (1)
From the second sentence, we know that:
p + c = 244.50 (2)
And from the third sentence, we know that:
c = 5s (3)
We can use equation (2) to solve for "p":
p = 244.50 - c
Then we can substitute that into equation (1) and also substitute equation (3) for "c":
(244.50 - c) + s + 5s = 100.90
Simplifying:
6s = 344.60
s = 57.43
Now we can use equation (3) to find "c":
c = 5s = 5(57.43) = 287.15
So, Mr. Zubir paid $287.15 for the coat.
From the first sentence, we know that:
p + s + c = (1)
From the second sentence, we know that:
p + c = 244.50 (2)
And from the third sentence, we know that:
c = 5s (3)
We can use equation (2) to solve for "p":
p = 244.50 - c
Then we can substitute that into equation (1) and also substitute equation (3) for "c":
(244.50 - c) + s + 5s = 100.90
Simplifying:
6s = 344.60
s = 57.43
Now we can use equation (3) to find "c":
c = 5s = 5(57.43) = 287.15
So, Mr. Zubir paid $287.15 for the coat.
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