Question

Mr Zubir bought a pair of pants, a shirt and a coat. The pants
and the shirt cost $100.90. The pants and the coat cost $244.50.
The coat cost 5 times as much as the shirt. How much did
Mr Zubir pay for the coat?

Answer 1

Let's call the cost of the pants "p", the cost of the shirt "s", and the cost of the coat "c".

From the first sentence, we know that:

p + s + c = (1)

From the second sentence, we know that:

p + c = 244.50 (2)

And from the third sentence, we know that:

c = 5s (3)

We can use equation (2) to solve for "p":

p = 244.50 - c

Then we can substitute that into equation (1) and also substitute equation (3) for "c":

(244.50 - c) + s + 5s = 100.90

Simplifying:

6s = 344.60

s = 57.43

Now we can use equation (3) to find "c":

c = 5s = 5(57.43) = 287.15

So, Mr. Zubir paid $287.15 for the coat.

Answer 2

The coat cost more than the pants and the coat together?

Redoing

p + s = 100.90
p + c = 244.50
----------------------- subtract
s - c = - 143.60

and
c = 5 s
so
s - 5 s = -143.60
-4 s = -143.60
s = 35.90 for a shirt
now
c = 5 s = 179.50