Question
A bus travels 9 miles north and 4 miles west from its original location. How far is the bus from the original location?
9.8 miles
13 miles
8.1 miles
97 miles
9.8 miles
13 miles
8.1 miles
97 miles
Answers
We can use the Pythagorean theorem to find the answer:
c^2 = a^2 + b^2
where c is the distance from the original location, and a and b are the distances traveled north and west respectively.
Plugging in the values:
c^2 = 9^2 + 4^2
c^2 = 81 + 16
c^2 = 97
Taking the square root of both sides:
c ≈ 9.85
Therefore, the bus is approximately 9.85 miles from its original location, so the closest answer is 9.8 miles.
c^2 = a^2 + b^2
where c is the distance from the original location, and a and b are the distances traveled north and west respectively.
Plugging in the values:
c^2 = 9^2 + 4^2
c^2 = 81 + 16
c^2 = 97
Taking the square root of both sides:
c ≈ 9.85
Therefore, the bus is approximately 9.85 miles from its original location, so the closest answer is 9.8 miles.
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