The answer is D: 2x≥11+13.
When we substitute x=12, 13, and 14 in inequality D, we get:
2(12) ≥ 11+13
24 ≥ 24 (True)
2(13) ≥ 11+13
26 ≥ 24 (True)
2(14) ≥ 11+13
28 ≥ 24 (True)
Thus, inequality D has solutions that include 12, 13, and 14.
Which inequality has solutions that include 12, 13, and 14?(1 point)
Responses
A :2x≥34−6
B: 2x<13+15
C: 2x≤12
D: 2x≥11+13
1 answer