Asked by Valentina
The bearig of Q from P is 300° and the bearig of R from Q is 210°.if Q is equidistant from P and R, find the bearing of R from P
Answers
Answered by
oobleck
if you draw the diagram, you can see that ∆PQR is an isosceles right triangle, so ∡P = 45°
thus, the bearing of R from P is 300-45 = 255°
thus, the bearing of R from P is 300-45 = 255°
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