find the vertical asymptote of f(x)=1/e^x +1

Answer 1

The vertical asymptote of a function occurs at the values of x that make the denominator zero. In this case, the denominator is e^x + 1.

Setting the denominator equal to zero, we get:

e^x + 1 = 0

Subtracting 1 from both sides, we get:

e^x = -1

But there is no real number x that makes e^x equal to a negative number. Therefore, there is no vertical asymptote for this function.