Asked by Stephanie

I burned a candle for 3 minutes. It started with a mass of 38.53g (C25H52). It ended with a mass of 38.48g. What mass of water was produced in three minutes? If I burned the candle all day, what mass of the candle would react?
Answered by DrBob222
38.53-38.48 = 0.05 gram of C25H52 that burned.
Convert 0.05 g C25H52 to moles. Moles = grams/molar mass.
Using the coefficients in the balanced equation, convert moles C25H52 to moles H2O.
Convert moles H2O to grams. grams = moles x molar mass.
Answered by Stephanie
would the answer for the first question be .06654 g H2O?
Answered by DrBob222
I obtained 0.065 g but I think we're allowed only one sig figure.
Answered by Monica
What would be the answer to the second question then?
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