Asked by Sinachi
If α and β are the roots of the quadratic equation 3x^2-4x+7=0 find 1/α^2 + 1/β^2
Answers
Answered by
oobleck
3x^2-4x+7 has roots
a=(2+i√17)/3 and b=(2-i√17)/3
so 1/a^2 + 1/b^2 = -26/49
a=(2+i√17)/3 and b=(2-i√17)/3
so 1/a^2 + 1/b^2 = -26/49
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