Question
What is (-4,9) (2,-9) in standard form
Answers
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To write the equation of a line passing through the points (-4,9) and (2,-9) in standard form, we first need to find the slope (m) and the y-intercept (b).
1. Calculate the slope (m):
m = (y2 - y1)/(x2 - x1)
m = (-9 - 9)/(2 - (-4))
m = (-18)/6
m = -3
2. Use the point-slope form to find the equation of the line (use the slope and one of the points):
y - y1 = m(x - x1)
y - 9 = -3(x - (-4))
3. Simplify and convert the equation to the standard form (Ax + By = C):
y - 9 = -3(x + 4)
y - 9 = -3x - 12
3x + y = -3
So, the equation of the line passing through the points (-4,9) and (2,-9) in standard form is 3x + y = -3.
1. Calculate the slope (m):
m = (y2 - y1)/(x2 - x1)
m = (-9 - 9)/(2 - (-4))
m = (-18)/6
m = -3
2. Use the point-slope form to find the equation of the line (use the slope and one of the points):
y - y1 = m(x - x1)
y - 9 = -3(x - (-4))
3. Simplify and convert the equation to the standard form (Ax + By = C):
y - 9 = -3(x + 4)
y - 9 = -3x - 12
3x + y = -3
So, the equation of the line passing through the points (-4,9) and (2,-9) in standard form is 3x + y = -3.