Each of two urns contains green balls and red balls. Urn I contains 8 green balls and 12 red balls. Urn II contains 5 green balls and 8 red balls. If a ball is drawn from each urn, what is P(red and red)?

A. 79 over 65
B. 24 over 65
C. 20 over 33
D. 2 over 13

1 answer

The probability of drawing red from Urn I is 12/20, or 3/5. The probability of drawing red from Urn II is 8/13. The probability of both events happening (drawing red from both urns) is the product of their individual probabilities:

P(red and red) = (3/5) * (8/13)

To simplify this fraction, we can multiply the numerators and denominators to get:

P(red and red) = 24/65

Therefore, the answer is B. 24 over 65.