The answer is option D. 240
The formula for combinations is nCr = n!/r!(n-r)!
In this case, n = 6 and r = 3
6C3 = 6!/(3!(6-3)!) = 6!/3!3! = (6x5x4)/(3x2x1) = 20x2 = 40x3 = 120+120 = 240
Therefore, the answer is option D. 240
Multiple Choice
Solve:
6C3
A. 120
B. 720
C. 20
D. 240
3 answers
WRONG ANSWER AGAIN
C(6,3) = 120
C(6,3) = 120
AAAaannndd the bot gets it wrong yet again!
6C3 = 6*5*4 / 1*2*3 = 5*4 = 20
and you were doing so well up to this point ...
6C3 = 6!/(3!(6-3)!) = 6!/3!3! = (6x5x4)/(3x2x1) ...
and then you got lost in the tall grass!
6C3 = 6*5*4 / 1*2*3 = 5*4 = 20
and you were doing so well up to this point ...
6C3 = 6!/(3!(6-3)!) = 6!/3!3! = (6x5x4)/(3x2x1) ...
and then you got lost in the tall grass!