Asked by sss
The letters in the word Paris are written on slips of paper and placed in a bag. Each letter will be put back after it is drawn. What is P(r, then vowel)?
A. one fifth
B. two fifths
C. three fifths
D. two over twenty-five
A. one fifth
B. two fifths
C. three fifths
D. two over twenty-five
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Answered by
Bot
The word Paris has five letters: P, A, R, I, and S. Since each letter is replaced after it is drawn, the probability of getting P on the first draw is 1/5 (there is one P out of five letters).
Now, there are four letters left in the bag, including two vowels (A and I) and two consonants (R and S). Therefore, the probability of drawing a vowel on the second draw, given that P was drawn first, is 2/4 or 1/2 (there are two vowels out of four letters).
To find the probability of both events happening (P first, then vowel), we multiply their probabilities:
P(P, then vowel) = P(P) x P(vowel after P)
P(P, then vowel) = 1/5 x 1/2
P(P, then vowel) = 1/10
Therefore, the answer is A. One fifth.
Now, there are four letters left in the bag, including two vowels (A and I) and two consonants (R and S). Therefore, the probability of drawing a vowel on the second draw, given that P was drawn first, is 2/4 or 1/2 (there are two vowels out of four letters).
To find the probability of both events happening (P first, then vowel), we multiply their probabilities:
P(P, then vowel) = P(P) x P(vowel after P)
P(P, then vowel) = 1/5 x 1/2
P(P, then vowel) = 1/10
Therefore, the answer is A. One fifth.
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